Direct Shear Test
1. In a direct shear test, the shear stress (τ) is calculated by dividing the shear force (F) by:
2. The drainage conditions in a direct shear test can be best described as:
3. The primary reason for performing multiple direct shear tests on the same soil at different normal loads is to:
4. For a dry sand, the cohesion (c) is typically:
5. Which of the following statements about the failure plane in a direct shear test is true?
6. If a soil specimen in a direct shear test has an area of 36 cm² and fails under a shear force of 180 N, the shear stress at failure is:
7. A direct shear test was conducted on a cohesionless soil (c = 0) specimen under a normal stress of 200 kN/m². The specimen failed at a shear stress of 100 kN/m². Determine the angle of internal friction (φ).
8. A direct shear test on a sand specimen yielded an angle of internal friction of 35 degrees. If the normal stress applied is 150 kN/m², and the cohesion is zero, what is the shear strength of the soil?
9. A direct shear test was conducted on a soil with c = 20 kPa and φ = 30 degrees. If the normal stress is 100 kPa, the shear strength is: